Integrand size = 32, antiderivative size = 38 \[ \int \frac {1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \, dx=-\frac {1}{4 e (d+e x) \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \]
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Time = 0.01 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {656, 621} \[ \int \frac {1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \, dx=-\frac {1}{4 e (d+e x) \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \]
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Rule 621
Rule 656
Rubi steps \begin{align*} \text {integral}& = c \int \frac {1}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx \\ & = -\frac {1}{4 e (d+e x) \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.68 \[ \int \frac {1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \, dx=-\frac {c (d+e x)}{4 e \left (c (d+e x)^2\right )^{5/2}} \]
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Time = 2.50 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.71
method | result | size |
risch | \(-\frac {1}{4 c \left (e x +d \right )^{3} \sqrt {c \left (e x +d \right )^{2}}\, e}\) | \(27\) |
gosper | \(-\frac {1}{4 e \left (e x +d \right ) \left (c \,x^{2} e^{2}+2 x c d e +c \,d^{2}\right )^{\frac {3}{2}}}\) | \(35\) |
default | \(-\frac {1}{4 e \left (e x +d \right ) \left (c \,x^{2} e^{2}+2 x c d e +c \,d^{2}\right )^{\frac {3}{2}}}\) | \(35\) |
trager | \(\frac {\left (e^{3} x^{3}+4 d \,e^{2} x^{2}+6 d^{2} e x +4 d^{3}\right ) x \sqrt {c \,x^{2} e^{2}+2 x c d e +c \,d^{2}}}{4 c^{2} d^{4} \left (e x +d \right )^{5}}\) | \(68\) |
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Leaf count of result is larger than twice the leaf count of optimal. 97 vs. \(2 (34) = 68\).
Time = 0.29 (sec) , antiderivative size = 97, normalized size of antiderivative = 2.55 \[ \int \frac {1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \, dx=-\frac {\sqrt {c e^{2} x^{2} + 2 \, c d e x + c d^{2}}}{4 \, {\left (c^{2} e^{6} x^{5} + 5 \, c^{2} d e^{5} x^{4} + 10 \, c^{2} d^{2} e^{4} x^{3} + 10 \, c^{2} d^{3} e^{3} x^{2} + 5 \, c^{2} d^{4} e^{2} x + c^{2} d^{5} e\right )}} \]
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\[ \int \frac {1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \, dx=\int \frac {1}{\left (c \left (d + e x\right )^{2}\right )^{\frac {3}{2}} \left (d + e x\right )^{2}}\, dx \]
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Time = 0.19 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.61 \[ \int \frac {1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \, dx=-\frac {1}{4 \, {\left (c^{\frac {3}{2}} e^{5} x^{4} + 4 \, c^{\frac {3}{2}} d e^{4} x^{3} + 6 \, c^{\frac {3}{2}} d^{2} e^{3} x^{2} + 4 \, c^{\frac {3}{2}} d^{3} e^{2} x + c^{\frac {3}{2}} d^{4} e\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.61 \[ \int \frac {1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \, dx=-\frac {1}{4 \, {\left (e x + d\right )}^{4} c^{\frac {3}{2}} e \mathrm {sgn}\left (e x + d\right )} \]
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Time = 9.93 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.97 \[ \int \frac {1}{(d+e x)^2 \left (c d^2+2 c d e x+c e^2 x^2\right )^{3/2}} \, dx=-\frac {\sqrt {c\,d^2+2\,c\,d\,e\,x+c\,e^2\,x^2}}{4\,c^2\,e\,{\left (d+e\,x\right )}^5} \]
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